5(2x^2-1)-(10x^2)=-(x+2)

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Solution for 5(2x^2-1)-(10x^2)=-(x+2) equation:


Simplifying
5(2x2 + -1) + -1(10x2) = -1(x + 2)

Reorder the terms:
5(-1 + 2x2) + -1(10x2) = -1(x + 2)
(-1 * 5 + 2x2 * 5) + -1(10x2) = -1(x + 2)
(-5 + 10x2) + -1(10x2) = -1(x + 2)

Remove parenthesis around (10x2)
-5 + 10x2 + -1 * 10x2 = -1(x + 2)

Multiply -1 * 10
-5 + 10x2 + -10x2 = -1(x + 2)

Combine like terms: 10x2 + -10x2 = 0
-5 + 0 = -1(x + 2)
-5 = -1(x + 2)

Reorder the terms:
-5 = -1(2 + x)
-5 = (2 * -1 + x * -1)
-5 = (-2 + -1x)

Solving
-5 = -2 + -1x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add 'x' to each side of the equation.
-5 + x = -2 + -1x + x

Combine like terms: -1x + x = 0
-5 + x = -2 + 0
-5 + x = -2

Add '5' to each side of the equation.
-5 + 5 + x = -2 + 5

Combine like terms: -5 + 5 = 0
0 + x = -2 + 5
x = -2 + 5

Combine like terms: -2 + 5 = 3
x = 3

Simplifying
x = 3

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